0000022928 00000 n 210 738

0000037135 00000 n 0000038217 00000 n 0000035292 00000 n 0000266624 00000 n 0000347322 00000 n Curved surfaces . 0000036424 00000 n 0000036142 00000 n 0000034221 00000 n 0000036236 00000 n

0000029389 00000 n 0000032911 00000 n 0000032210 00000 n 0000031034 00000 n 0000323810 00000 n 0000321969 00000 n 0000317817 00000 n 0000027683 00000 n 0000034501 00000 n 0000026157 00000 n 0000028257 00000 n 0000284305 00000 n 0000024683 00000 n 0000024967 00000 n 0000029342 00000 n 0000028399 00000 n

>> 0000032723 00000 n 0000268467 00000 n 0000025634 00000 n 0000024023 00000 n 0000354013 00000 n 0000073714 00000 n 0000034407 00000 n 0000318041 00000 n 0000163675 00000 n 0000118307 00000 n 0000030335 00000 n 0000276520 00000 n 0000336424 00000 n 0000339342 00000 n 0000317468 00000 n 0000024919 00000 n 0000208451 00000 n 0000038405 00000 n 0000348082 00000 n The density of water is 103 kg/m 3 . Hydrostatic Pressure immersed in water • To compare theexperitlimental position with the th ti ltheoretical results Background theory 0000314304 00000 n

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0000052806 00000 n

endobj 0000026970 00000 n 0000335967 00000 n 0000027923 00000 n 0000036189 00000 n 0000337440 00000 n Hydrostatic Pressure Instructor: Seo, Il Won (35-310) Web: www.ehlab.snu.ac.kr ObjectivesObjectives Chapter 1 Hydrostatic Pressure • To determine the center position of pressure of a plane surface Chapter 1. 0000035387 00000 n 0000315528 00000 n Compute (a) the total hydrostatic force and (b) the resultant center of pressure of the fluid on the right-hand side of the tank. 4 0 obj 0000036001 00000 n 0000033616 00000 n Chapter 3 Pressure and Fluid Statics Solutions Manual for Fluid Mechanics: Fundamentals and Applications CHAPTER 3 PRESSURE AND FLUID STATICS 0000287709 00000 n 0000331195 00000 n 0000025492 00000 n 0000305876 00000 n 0000233461 00000 n endstream endobj 135 0 obj <> endobj 136 0 obj <>/ProcSet[/PDF/Text]/XObject<>>>/Rotate 0/Type/Page>> endobj 137 0 obj <>stream 0000110519 00000 n 0000354629 00000 n 0000039051 00000 n 0000325972 00000 n 0000306655 00000 n 0000031405 00000 n %��������� 0000253532 00000 n 0000314014 00000 n 0000028917 00000 n 0000335053 00000 n

0000308729 00000 n 0000322302 00000 n 0000266236 00000 n 0000025015 00000 n 0000308547 00000 n 0000035766 00000 n 0000027779 00000 n 0000332239 00000 n Plane (flat) surfaces 2. 0000311866 00000 n 0000030569 00000 n 0000032489 00000 n 0000263988 00000 n 0000336914 00000 n 0000035813 00000 n Everest suffer other physical problems due to the low pressure. 0000023739 00000 n 0000061239 00000 n 0000291745 00000 n 0000038593 00000 n 0000341196 00000 n

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Analysis Using the psia to kPa units conversion factor, 1034 kPa 1 psia 6.895 kPa P (150 psia) 3-10E Solution The pressure in a tank in SI unit is given.
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0000277842 00000 n 0000311781 00000 n 0000055687 00000 n 0000036800 00000 n 0000033240 00000 n 0000303481 00000 n 0000284910 00000 n 0000037512 00000 n @����%���g���8A|��c�b�-�����7�D; t+8L�w�����g�����b�9�3X0B�šY��CO�v��4� �u��Pn��#*�/��\ �3#�⋠��h�Ш�9`�0�&�im��#�2�Ur������)rb �GGGG��``� s]: \A�Kƒ +aN�rU#: z`��2���,��J@Z�5��� �P�(� � w����5��9�I00x0�������D��;څy�M�?�O�f��;.Y��ph����l �s��a�^���� H3�G� �s�� 0000253114 00000 n 0000030099 00000 n 0000035197 00000 n Solution Divide the end panel into three pans as sketched in Fig. 0000025063 00000 n Calculate the horizontal component of hydrostatic force (R f): As stated above, the value R f is calculated … 0000035339 00000 n 9 0 obj 0000034913 00000 n 0000024118 00000 n

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